integral of ((x^3+6x^2+2x+3))/(x^2+6x+1)

解

\int \frac{( x ^{3} + 6 x ^{2} + 2 x + 3 )}{x ^{2} + 6 x + 1} d x

\frac{x ^{2}}{2} + \frac{2 2 + 3}{4 2} ln x + 3 + 22 + \frac{2 2 - 3}{4 2} ln x + 3 - 22 - \frac{3}{4 2} (ln \frac{x + 3}{2 2} + 1 - ln \frac{x + 3}{2 2} - 1) + C

解答ステップ

\int \frac{x ^{3} + 6 x ^{2} + 2 x + 3}{x ^{2} + 6 x + 1} d x

長除法

\frac{x ^{3} + 6 x ^{2} + 2 x + 3}{x ^{2} + 6 x + 1} : x + \frac{x + 3}{x ^{2} + 6 x + 1}

= \int x + \frac{x + 3}{x ^{2} + 6 x + 1} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{x + 3}{x ^{2} + 6 x + 1} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{x + 3}{x ^{2} + 6 x + 1} d x = \frac{2 2 + 3}{4 2} ln x + 3 + 22 + \frac{2 2 - 3}{4 2} ln x + 3 - 22 - \frac{3}{4 2} (ln \frac{x + 3}{2 2} + 1 - ln \frac{x + 3}{2 2} - 1)

= \frac{x ^{2}}{2} + \frac{2 2 + 3}{4 2} ln x + 3 + 22 + \frac{2 2 - 3}{4 2} ln x + 3 - 22 - \frac{3}{4 2} (ln \frac{x + 3}{2 2} + 1 - ln \frac{x + 3}{2 2} - 1)

定数を解答に追加する

= \frac{x ^{2}}{2} + \frac{2 2 + 3}{4 2} ln x + 3 + 22 + \frac{2 2 - 3}{4 2} ln x + 3 - 22 - \frac{3}{4 2} (ln \frac{x + 3}{2 2} + 1 - ln \frac{x + 3}{2 2} - 1) + C