What is the integral from 0 to pi/4 of (sec^2(x)) ?

The integral from 0 to pi/4 of (sec^2(x)) is 1

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integral from 0 to pi/4 of (sec^2(x))

\int_{0}^{\frac{π}{4}} (sec^{2} (x)) d x

1

Solution steps

\int_{0}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 1

\int x^{5} cos (1 - x^{6}) d x

x \to 0 lim (5 x - 3)

\int \frac{x ^{3} - 2 x}{x} d x

\int (6 x + 1) \cdot 2 x - 3 d x

t an g e n t f (x) = (1 + 2 x) (3 - 2 x), at x = 1

What is the integral from 0 to pi/4 of (sec^2(x)) ?
The integral from 0 to pi/4 of (sec^2(x)) is 1