derivative of 1+1/(4x)

解答

\frac{d}{d x} (1 + \frac{1}{4 x})

- \frac{1}{4 x ^{2}}

求解步骤

\frac{d}{d x} (1 + \frac{1}{4 x})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{1}{4 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{4 x}) = - \frac{1}{4 x ^{2}}

= 0 - \frac{1}{4 x ^{2}}

化简

= - \frac{1}{4 x ^{2}}

l a pl a ce t r an s f or m \frac{1}{10} e^{4 t} + \frac{9}{10} e^{- 6 t}

d er i v a t i v e f (x) = 2 x^{2} - 16 x + 35

\int (- 3 x + 4 x) d x

d y - (y - 7)^{2} d x = 0

\int e^{4 x} cos (2 x) d x