(\partial)/(\partial x)(2sqrt(xyz))

解答

\frac{\partial}{\partial x} (2 x yz)

\frac{y z}{x}

求解步骤

\frac{\partial}{\partial x} (2 x yz)

将

y, z

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x yz)

使用连锁律:

\frac{1}{2 x yz} \frac{\partial}{\partial x} (x yz)

= \frac{1}{2 x yz} \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (x yz) = yz

= 2 \cdot \frac{1}{2 x yz} yz

化简

2 \cdot \frac{1}{2 x yz} yz : \frac{y z}{x}

= \frac{y z}{x}

d er i v a t i v e y = \frac{3 x}{x}

\int \frac{ln ^{6} ( x )}{x} d x

x \to 0 lim (\frac{3 sin ( x ) + x}{x})

\int \frac{1}{3 x ( 5 + x )} d x

n or ma l y = x^{4} + 7 e^{x}, (0, 7)