derivative g(u)=sqrt(2u)+sqrt(3u)

解答

导数

g (u) = 2 u + 3 u

\frac{1}{2 u} + \frac{3}{2 u}

求解步骤

\frac{d}{d u} (2 u + 3 u)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (2 u) + \frac{d}{d u} (3 u)

\frac{d}{d u} (2 u) = \frac{1}{2 u}

\frac{d}{d u} (3 u) = \frac{3}{2 u}

= \frac{1}{2 u} + \frac{3}{2 u}

d er i v a t i v e cos ((π x)^{3})

d er i v a t i v e ln (r)

in v erse l a pl a ce \frac{1}{( s - 1 ) ( s - 2 ) ( s - 3 )}

\int_{0}^{\frac{1}{2}} 7 arccos (x) d x

y^{^{'}} = 14 x y - 2 x