y^'=-2y

Lösung

y^{^{'}} = - 2 y

y = e^{- 2 t + c_{1}}

Schritte zur Lösung

y^{'} (t) = - 2 y

Solve separable ODE:

y = e^{- 2 t + c_{1}}

y = e^{- 2 t + c_{1}}

\int (2 x - 4) (x^{2} - 4 x + 3)^{5} d x

2 t y^{^{'}} + 4 y = 3

\int \frac{9}{x - 4} d x

\frac{d}{d x} (tan (4 x^{5}))

d er i v a t i v e y = \frac{t}{( t - 8 ) ^{2}}