derivative s(t)=-9.8t^2+2t+1

Lösung

ableitung von

s (t) = - 9.8 t^{2} + 2 t + 1

- 19.6 t + 2

Schritte zur Lösung

\frac{d}{d t} (- 9.8 t^{2} + 2 t + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (9.8 t^{2}) + \frac{d}{d t} (2 t) + \frac{d}{d t} (1)

\frac{d}{d t} (9.8 t^{2}) = 19.6 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (1) = 0

= - 19.6 t + 2 + 0

Vereinfache

= - 19.6 t + 2

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