What is the solution for 7(ln(y))y^'-x^3y=0 ?

The solution for 7(ln(y))y^'-x^3y=0 is y=e^{sqrt((x^4+c_{1))/(14)}},y=e^{-sqrt((x^4+c_{1))/(14)}}

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7(ln(y))y^'-x^3y=0

7 (ln (y)) y^{^{'}} - x^{3} y = 0

y = e^{\frac{x ^{4} + c _{1}}{14}}, y = e^{- \frac{x ^{4} + c _{1}}{14}}

Solution steps

7 (ln (y)) y^{'} (x) - x^{3} y = 0

Solve separable ODE:

y = e^{\frac{x ^{4} + c _{1}}{14}}, y = e^{- \frac{x ^{4} + c _{1}}{14}}

y = e^{\frac{x ^{4} + c _{1}}{14}}, y = e^{- \frac{x ^{4} + c _{1}}{14}}

\frac{e ^{- 2 s}}{s ( s + 1.1 )}

\int_{0}^{1} x sin (π x) d x

y = \frac{x}{( e ^{x} )}

(e^{t^{2}})^{^{'}}

y = \frac{2}{x - 8}, (10, 1)

What is the solution for 7(ln(y))y^'-x^3y=0 ?
The solution for 7(ln(y))y^'-x^3y=0 is y=e^{sqrt((x^4+c_{1))/(14)}},y=e^{-sqrt((x^4+c_{1))/(14)}}