(dy)/(dx)= 1/(xsin(y)+2sin(2y))

Lösung

\frac{d y}{d x} = \frac{1}{x sin ( y ) + 2 sin ( 2 y )}

y = arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn, y = - arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn

Schritte zur Lösung

\frac{d y}{d x} = \frac{1}{x sin ( y ) + 2 sin ( 2 y )}

Solve exact ODE:

y = arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn, y = - arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn

y = arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn, y = - arccos (W (- \frac{c _{1}}{4 e ^{\frac{- x + 4}{4}}}) - \frac{1}{4} x + 1) + 2 πn

\int \frac{x}{x ^{2}} d x

x^{2} y^{^{'}} + x y = 3 y^{3}

\int 54 sec^{4} (x) d x

d er i v a t i v e 3 y

\int_{0}^{1} x^{10} + 1 0^{x} d x