What is the derivative of sin(3xy) ?

The derivative of sin(3xy) is cos(3xy)*3(y+x(dy)/(dx))

What is the first derivative of sin(3xy) ?

The first derivative of sin(3xy) is cos(3xy)*3(y+x(dy)/(dx))

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\frac{d}{d x} (sin (3 x y))

cos (3 x y) \cdot 3 (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (sin (3 x y))

Apply the chain rule:

cos (3 x y) \frac{d}{d x} (3 x y)

= cos (3 x y) \frac{d}{d x} (3 x y)

\frac{d}{d x} (3 x y) = 3 (y + x \frac{d y}{d x})

= cos (3 x y) \cdot 3 (y + x \frac{d y}{d x})

d er i v a t i v e y = 4 sec (5 x)

\frac{d}{d x} (sin (2 x + 1))

t an g e n t \frac{10 x}{1 + x ^{2}}

\frac{d}{d x} (sinh (5 x))

\int \frac{( 2 x + 5 )}{x ^{2} + 5 x + 6} d x

What is the derivative of sin(3xy) ?
The derivative of sin(3xy) is cos(3xy)*3(y+x(dy)/(dx))
What is the first derivative of sin(3xy) ?
The first derivative of sin(3xy) is cos(3xy)*3(y+x(dy)/(dx))