What is the d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) ?

The d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) is -1/(4{r)^{3/2}}-6/(49{r)^{13/7}}

What is the first d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) ?

The first d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) is -1/(4{r)^{3/2}}-6/(49{r)^{13/7}}

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\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}})

- \frac{1}{4 r ^{\frac{3}{2}}} - \frac{6}{49 r ^{\frac{13}{7}}}

Solution steps

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (\frac{1}{2 r}) + \frac{d}{d r} (\frac{1}{7 r ^{\frac{6}{7}}})

\frac{d}{d r} (\frac{1}{2 r}) = - \frac{1}{4 r ^{\frac{3}{2}}}

\frac{d}{d r} (\frac{1}{7 r ^{\frac{6}{7}}}) = - \frac{6}{49 r ^{\frac{13}{7}}}

= - \frac{1}{4 r ^{\frac{3}{2}}} - \frac{6}{49 r ^{\frac{13}{7}}}

\int cos (t) sin^{4} (t) d t

\frac{d}{d x} (e^{- 5})

\int 21 x^{20} d x

\int \frac{13}{x ^{3} - 125} d x

\frac{d}{d θ} (cos (θ^{2}))

What is the d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) ?
The d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) is -1/(4{r)^{3/2}}-6/(49{r)^{13/7}}
What is the first d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) ?
The first d/(d{r)}(1/(2sqrt({r))}+1/(7{r)^{6/7}}) is -1/(4{r)^{3/2}}-6/(49{r)^{13/7}}