What is the first derivative of 6x-5 ?

The first derivative of 6x-5 is 6

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derivative of 6x-5

\frac{d}{d x} (6 x - 5)

6

Solution steps

\frac{d}{d x} (6 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) - \frac{d}{d x} (5)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (5) = 0

= 6 - 0

Simplify

= 6

\frac{\partial}{\partial x} (y x - y^{2} - x + 3 y)

y^{^{''}} - 2 y^{^{'}} + y = 2 e^{x}

x \to - 1 + lim (arcsin (x))

\frac{d}{d x} ((4 x + 5)^{2})

f (x) = sin (x^{3})