(\partial)/(\partial l)(2pisqrt(l/({g))})

解答

\frac{\partial}{\partial l} (2 π \frac{l}{g})

\frac{π}{l g}

求解步骤

\frac{\partial}{\partial l} (2 π \frac{l}{g})

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 π \frac{\partial}{\partial l} (\frac{l}{g})

使用连锁律:

\frac{1}{2 \frac{l}{g}} \frac{\partial}{\partial l} (\frac{l}{g})

= \frac{1}{2 \frac{l}{g}} \frac{\partial}{\partial l} (\frac{l}{g})

\frac{\partial}{\partial l} (\frac{l}{g}) = \frac{1}{g}

= 2 π \frac{1}{2 \frac{l}{g}} \cdot \frac{1}{g}

化简

2 π \frac{1}{2 \frac{l}{g}} \cdot \frac{1}{g} : \frac{π}{l g}

= \frac{π}{l g}

\frac{d}{d x} (ln (\frac{x ^{2} - 1}{x ^{2} + 1}))

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x

\frac{d}{d x} (sin (\frac{π}{2} x))

\int_{0}^{6} \frac{7 t}{( t - 7 ) ^{2}} d t

\int cos (4 x) cos (8 x) d x