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Beliebt Rechnen >

arclength f(x)=x^2+2x,0<x<6

Lösung

bogenlänge

f (x) = x^{2} + 2 x, 0 < x < 6

Lösung

\frac{7 197 - 5}{2} + \frac{1}{4} ln (14 + 197) - \frac{1}{4} ln (2 + 5)

+1

Dezimale

48.47926 \dots

Schritte zur Lösung

Bogenlängenformel anwenden:

\int_{0}^{6} 1 + (2 x + 2)^{2} d x

Löse

\int_{0}^{6} 1 + (2 x + 2)^{2} d x : \frac{7 197 - 5}{2} + \frac{1}{4} ln (14 + 197) - \frac{1}{4} ln (2 + 5)

Die Bogenlänge ist:

= \frac{7 197 - 5}{2} + \frac{1}{4} ln (14 + 197) - \frac{1}{4} ln (2 + 5)

Graph

Beliebte Beispiele

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\frac{d}{d x} y = 6 x

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\frac{d y}{d x} y = tan (x)