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Frequently Asked Questions (FAQ)
What is the solution for y^{'''}+3y^{''}=-36x^2+12x+42 ?
- The solution for y^{'''}+3y^{''}=-36x^2+12x+42 is y=c_{1}e^{-3x}+c_{2}+c_{3}x-x^4+2x^3+5x^2