y^{''}+25y^'+1/(0.046)y=0

Lösung

y^{^{''}} + 25 y^{^{'}} + \frac{1}{0.046} y = 0

y = c_{1} e^{\frac{( - 25 + 538.04347 \dots ) t}{2}} + c_{2} e^{\frac{( - 25 - 538.04347 \dots ) t}{2}}

Schritte zur Lösung

y^{''} (t) + 25 y^{'} (t) + \frac{1}{0.046} y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 25 + 538.04347 \dots ) t}{2}} + c_{2} e^{\frac{( - 25 - 538.04347 \dots ) t}{2}}

y = c_{1} e^{\frac{( - 25 + 538.04347 \dots ) t}{2}} + c_{2} e^{\frac{( - 25 - 538.04347 \dots ) t}{2}}

y^{^{'''}} + 8 y^{^{'}} = 0

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} = 0

y^{^{''}} - 3 y^{^{'}} = 0, y (0) = 2 - 2 e^{3}, y (1) = 0

y^{^{''}} - 19 y^{^{'}} + 90 y = 0

y^{^{''}} + 5 y^{^{'}} + \frac{29}{4} y = 0, y (0) = 1, y^{^{'}} (0) = - \frac{7}{2}