cy^{''}+aby^'=0

Lösung

c y^{^{''}} + ab y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{ab t}{c}}

Schritte zur Lösung

c y^{''} (t) + ab y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{ab t}{c}}

y = c_{1} + c_{2} e^{- \frac{ab t}{c}}

3 y^{^{''}} + 35 y = 0, y (0) = 2, y^{^{'}} (0) = 9

(D^{3} + D^{2} - 2 D + 12) y = 0

y^{^{''}} + 3 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 3

3 y^{^{''}} = 4 y^{^{'}}

y^{^{''}} + y^{^{'}} = - cy