y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=8

Lösung

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 0, y^{^{'}} (0) = 8

y = 8 e^{5 t} t

Schritte zur Lösung

y^{''} (t) - 10 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = 8 e^{5 t} t

y = 8 e^{5 t} t

y^{^{''}} + 32 y^{^{'}} + 192 y = 0, y (0) = \frac{1}{6}, y^{^{'}} (0) = 2

y^{^{''}} + 15 y^{^{'}} + 50 y = 0, y (0) = 12, y^{^{'}} (0) = - 100

y^{^{''}} + 15 y^{^{'}} + 50 y = 0, y (0) = 12, y^{^{'}} (0) = - 105

x^{^{''}} + x^{^{'}} + 0.25 x = 0, x (0) = 2, x^{^{'}} (0) = \frac{1}{3}

y^{^{''}} + 9 y = 0, y (\frac{π}{6}) = 1, y (0) = - 1