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Beliebt Rechnen >

4y^{''}+7y^'+8y=0

Lösung

4 y^{^{''}} + 7 y^{^{'}} + 8 y = 0

Lösung

y = e^{- \frac{7 t}{8}} (c_{1} cos (\frac{79 t}{8}) + c_{2} sin (\frac{79 t}{8}))

Schritte zur Lösung

4 y^{''} (t) + 7 y^{'} (t) + 8 y = 0

Solve linear ODE:

y = e^{- \frac{7 t}{8}} (c_{1} cos (\frac{79 t}{8}) + c_{2} sin (\frac{79 t}{8}))

y = e^{- \frac{7 t}{8}} (c_{1} cos (\frac{79 t}{8}) + c_{2} sin (\frac{79 t}{8}))

Graph

Beliebte Beispiele

y^{''}+10y^'+9y=0,y(0)=2,y^'(0)=0

y^{^{''}} + 10 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 0

(d^2y)/(dt^2)-5(dy)/(dt)=0

\frac{d ^{2} y}{d t ^{2}} - 5 \frac{d y}{d t} = 0

x^{^{''}} - 3 x^{^{'}} = 0

y^{''}+4*y^'+4*y=0

y^{^{''}} + 4 \cdot y^{^{'}} + 4 \cdot y = 0

49y^{''}-14y^'+y=0

49 y^{^{''}} - 14 y^{^{'}} + y = 0