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Beliebt Rechnen >

y^{''}+4y^'+29y=0,y(0)=2,y^'(0)=0

Lösung

y^{^{''}} + 4 y^{^{'}} + 29 y = 0, y (0) = 2, y^{^{'}} (0) = 0

Lösung

y = e^{- 2 t} (2 cos (5 t) + \frac{4}{5} sin (5 t))

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + 29 y = 0

Solve linear ODE:

y = e^{- 2 t} (2 cos (5 t) + \frac{4}{5} sin (5 t))

y = e^{- 2 t} (2 cos (5 t) + \frac{4}{5} sin (5 t))

Graph

Beliebte Beispiele

y^{''}+2y^'-3y=0,y(0)=2,y^'(0)=10

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 2, y^{^{'}} (0) = 10

(d^4y)/(dx^4)+6(d^2y)/(dx^2)+9y=0

\frac{d ^{4} y}{d x ^{4}} + 6 \frac{d ^{2} y}{d x ^{2}} + 9 y = 0

9y^{'''}+12y^{''}+4y^'=0

9 y^{^{'''}} + 12 y^{^{''}} + 4 y^{^{'}} = 0

(D^3-2D^2-5D+6)y=0

(D^{3} - 2 D^{2} - 5 D + 6) y = 0

16y^{''}+88y^'+121y=0

16 y^{^{''}} + 88 y^{^{'}} + 121 y = 0