What is the solution for y^{''}-16y=0,y(0)=3 ?

The solution for y^{''}-16y=0,y(0)=3 is y=(3-c_{2})e^{4t}+c_{2}e^{-4t}

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y^{''}-16y=0,y(0)=3

y^{^{''}} - 16 y = 0, y (0) = 3

y = (3 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

Solution steps

y^{''} (t) - 16 y = 0

Solve linear ODE:

y = (3 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

y = (3 - c_{2}) e^{4 t} + c_{2} e^{- 4 t}

What is the solution for y^{''}-16y=0,y(0)=3 ?
The solution for y^{''}-16y=0,y(0)=3 is y=(3-c_{2})e^{4t}+c_{2}e^{-4t}