y^{''}-400y=0

Lösung

y^{^{''}} - 400 y = 0

y = c_{1} e^{20 t} + c_{2} e^{- 20 t}

Schritte zur Lösung

y^{''} (t) - 400 y = 0

Solve linear ODE:

y = c_{1} e^{20 t} + c_{2} e^{- 20 t}

y = c_{1} e^{20 t} + c_{2} e^{- 20 t}

y^{^{''}} + (1 + a) y = 0

y^{^{''}} - 8 y^{^{'}} + 15 y = 0, y (0) = 1, y^{^{'}} (0) = 1

9 x^{^{''}} - 12 x^{^{'}} + 4 x = 0

y^{^{'''}} - 5 y + 4 y = 0

y^{^{''''}} - y^{^{''}} = 2 (4 y^{^{''}})