Solution
Solution
Solution steps
Popular Examples
3y^{'''}-12y^'-4y^{''}=04y^{''}+4y^'+7y=05y^{''}-13y^'-6y=0y^{''}+48y^'=0y^{''}+2ay^'+(a^2+1)y=0,y(0)=1,y^'(0)=0
Frequently Asked Questions (FAQ)
What is 2u^{''}+7u^'-4\H(t)=0 ?
The answer to 2u^{''}+7u^'-4\H(t)=0 is 2*0+7*0-4\H(t(x))=0