49y^{''}-49y=0

Lösung

49 y^{^{''}} - 49 y = 0

y = c_{1} e^{t} + c_{2} e^{- t}

Schritte zur Lösung

49 y^{''} (t) - 49 y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t}

y = c_{1} e^{t} + c_{2} e^{- t}

\frac{d ^{2} y}{d x ^{2}} - 4 (\frac{d y}{d x}) - 32 y = 0

x^{^{''}} + 0.01 x^{^{'}} + x = 0

y^{^{''}} + 0 y^{^{'}} + 36 y = 0, y (0) = 4, y^{^{'}} (0) = 0

y^{^{''}} - y - 2 y = 0

y^{^{'''}} - 2 y^{^{''}} - y^{^{'}} + 2 y = 0, y (0) = 2