y^{''}+2y^'=0,y(0)=-28,y^'(0)=2

Lösung

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 28, y^{^{'}} (0) = 2

y = - e^{- 2 t} - 27

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) = 0

Solve linear ODE:

y = - e^{- 2 t} - 27

y = - e^{- 2 t} - 27

y^{^{''}} + 2 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 1

x^{^{''}} - 2 x^{^{'}} + 2 x = 0, x (0) = 0, x^{^{'}} (0) = 1

20 y^{^{''}} + 3 y^{^{'}} - 2 y = 0

3 \frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} - 8 y = 0

625 y^{^{''}} - 81 y = 0, y (0) = 9, y^{^{'}} (0) = 6