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Frequently Asked Questions (FAQ)
What is the solution for x^2y^{''}-3xy^'+5y=0,y(1)=-1,y^'(1)=4 ?
- The solution for x^2y^{''}-3xy^'+5y=0,y(1)=-1,y^'(1)=4 is y=x^2(-cos(ln(x))+6sin(ln(x)))