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Frequently Asked Questions (FAQ)
What is the solution for 2y^{''}-11y^'+5y=0,y(0)=13,y^'(0)=47 ?
- The solution for 2y^{''}-11y^'+5y=0,y(0)=13,y^'(0)=47 is y=9e^{5t}+4e^{t/2}