y^{''}-13y^'+42y=0

Lösung

y^{^{''}} - 13 y^{^{'}} + 42 y = 0

y = c_{1} e^{7 t} + c_{2} e^{6 t}

Schritte zur Lösung

y^{''} (t) - 13 y^{'} (t) + 42 y = 0

Solve linear ODE:

y = c_{1} e^{7 t} + c_{2} e^{6 t}

y = c_{1} e^{7 t} + c_{2} e^{6 t}

y^{^{''}} + 9 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 6 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = 5

y^{^{''}} + 4 y^{^{'}} - 3 y = 0

y^{^{''}} - 3 y^{^{'}} - 4 y = 0, y (0) = a, y^{^{'}} (0) = - 15

y^{^{''''}} - y^{^{'''}} - y^{^{''}} - y^{^{'}} - 2 y = 0