y^{''}+y^'+5y=0,y(0)=0

Lösung

y^{^{''}} + y^{^{'}} + 5 y = 0, y (0) = 0

y = c_{2} e^{- \frac{t}{2}} sin (\frac{19 t}{2})

Schritte zur Lösung

y^{''} (t) + y^{'} (t) + 5 y = 0

Solve linear ODE:

y = c_{2} e^{- \frac{t}{2}} sin (\frac{19 t}{2})

y = c_{2} e^{- \frac{t}{2}} sin (\frac{19 t}{2})

x^{^{''}} - 6 x^{^{'}} + 8 x = 0

2 y^{^{''}} + 2 y^{^{'}} - 2 y = 0

2 y^{^{''}} + 36 y^{^{'}} + 163 y = 0

y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} - 2 y = 0

3 y^{^{''}} + 7 y^{^{'}} + 2 y = 0