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Beliebt Rechnen >

y^{''}+2y^'+4y=0,y(0)=1,y^'(0)=-2

Lösung

y^{^{''}} + 2 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = - 2

Lösung

y = e^{- t} (cos (3 t) - \frac{1}{3} sin (3 t))

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = e^{- t} (cos (3 t) - \frac{1}{3} sin (3 t))

y = e^{- t} (cos (3 t) - \frac{1}{3} sin (3 t))

Graph

Beliebte Beispiele

y^{'''}-5y^{''}+7y^'-3y=0

y^{^{'''}} - 5 y^{^{''}} + 7 y^{^{'}} - 3 y = 0

y^{''}+4y=0,y^'(0)=2

y^{^{''}} + 4 y = 0, y^{^{'}} (0) = 2

(d^2y)/(dx^2)+(dy)/(dx)+1/4 y=0

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} + \frac{1}{4} y = 0

100y^{''}+200y^'+101y=0

100 y^{^{''}} + 200 y^{^{'}} + 101 y = 0

y^{^{''''}} - 8 y = 0