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Beliebt Rechnen >

x^{''}+2x^'+26x=0,x(0)=1,x^'(0)=4

Lösung

x^{^{''}} + 2 x^{^{'}} + 26 x = 0, x (0) = 1, x^{^{'}} (0) = 4

Lösung

x = e^{- t} (cos (5 t) + sin (5 t))

Schritte zur Lösung

x^{''} (t) + 2 x^{'} (t) + 26 x = 0

Solve linear ODE:

x = e^{- t} (cos (5 t) + sin (5 t))

x = e^{- t} (cos (5 t) + sin (5 t))

Graph

Beliebte Beispiele

y^{''''}+y^{'''}-7y^{''}-y^'+6y=0

y^{^{''''}} + y^{^{'''}} - 7 y^{^{''}} - y^{^{'}} + 6 y = 0

(d^2y)/(dx^2)=-k^2y

\frac{d ^{2} y}{d x ^{2}} = - k^{2} y

x^{''}+144x=0,x(0)=3,x^'(0)=-48

x^{^{''}} + 144 x = 0, x (0) = 3, x^{^{'}} (0) = - 48

2y^{''}-8y^'+6y=0

2 y^{^{''}} - 8 y^{^{'}} + 6 y = 0

y^{'''}+4y^{''}-11y^'+6y=0

y^{^{'''}} + 4 y^{^{''}} - 11 y^{^{'}} + 6 y = 0