We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for 2yy^'+2=y^2+2x,y(0)=8 ?
- The solution for 2yy^'+2=y^2+2x,y(0)=8 is y=sqrt(-2x+64e^x)