y^{'''}-2y^{''}=0

Lösung

y^{^{'''}} - 2 y^{^{''}} = 0

y = c_{1} e^{2 t} + c_{2} + c_{3} t

Schritte zur Lösung

y^{'''} (t) - 2 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} + c_{3} t

y = c_{1} e^{2 t} + c_{2} + c_{3} t

5 \frac{d ^{2} x}{d t ^{2}} + 3 \frac{d x}{d t} + 6 x = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 3

24 y^{^{''}} + 14 y^{^{'}} - 5 y = 0

4 y^{^{''}} + 24 y^{^{'}} + 37 y = 0, y (π) = 1, y^{^{'}} (π) = 0

y^{^{''''}} - 8 y^{^{''}} + 16 y = 0