θ^{''}(t)+(4k)/3 θ(t)=0

Lösung

θ^{^{''}} + \frac{4 k}{3} θ = 0

θ (t) = c_{1} cos (\frac{2 k t}{3}) + c_{2} sin (\frac{2 k t}{3})

Schritte zur Lösung

θ^{''} (t) + \frac{4 k}{3} θ (t) = 0

Solve linear ODE:

θ (t) = c_{1} cos (\frac{2 k t}{3}) + c_{2} sin (\frac{2 k t}{3})

θ (t) = c_{1} cos (\frac{2 k t}{3}) + c_{2} sin (\frac{2 k t}{3})

y^{^{''}} + 144 y = 0, y (0) = 3, y^{^{'}} (0) = - 48

y^{^{''}} + 4 y^{^{'}} - 12 y = 0, y (0) = 7, y^{^{'}} (0) = - 7

y^{^{''}} + 3 y^{^{'}} - y = 0

y^{^{'''}} + 2 y^{^{''}} = 0

y^{^{''}} - 8 y^{^{'}} + 16 y = 0, y (0) = 1, y^{^{'}} (0) = 1