y^{''}+cy=0

Lösung

y^{^{''}} + cy = 0

y = c_{1} cos (c t) + c_{2} sin (c t)

Schritte zur Lösung

y^{''} (t) + cy = 0

Solve linear ODE:

y = c_{1} cos (c t) + c_{2} sin (c t)

y = c_{1} cos (c t) + c_{2} sin (c t)

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 13 y = 0

y^{^{''}} - y^{^{'}} - 20 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 12 y^{^{'}} + 35 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = 11, y^{^{'}} (0) = 28

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = e^{2 x}