y^{''}+4y^'-5y=0,y(0)=2,y(0)=26

Lösung

y^{^{''}} + 4 y^{^{'}} - 5 y = 0, y (0) = 2, y (0) = 26

y = (2 - c_{2}) e^{t} + c_{2} e^{- 5 t}

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) - 5 y = 0

Solve linear ODE:

y = (2 - c_{2}) e^{t} + c_{2} e^{- 5 t}

y = (2 - c_{2}) e^{t} + c_{2} e^{- 5 t}

64 y^{^{''}} - y = 0, y (- 8) = 1, y^{^{'}} (- 8) = - 1

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = 0, y^{^{'}} (0) = - 7

y^{^{''}} + y^{^{'}} - 2 y = 0, y (0) = 0, y^{^{'}} (0) = 3

y^{^{'''}} + 4 y^{^{''}} - 4 y^{^{'}} - 16 y = 0

y^{^{''''}} - y^{^{'''}} - 3 y^{^{''}} + 5 y^{^{'}} - 2 y = 0