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Beliebt Rechnen >

(D^2-2D+5)y=0

Lösung

(D^{2} - 2 D + 5) y = 0

Lösung

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x))

Schritte zur Lösung

(D^{2} - 2 D + 5) y = 0

Solve linear ODE:

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x))

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x))

Graph

Beliebte Beispiele

y^{''}+10y^'+16y=0

y^{^{''}} + 10 y^{^{'}} + 16 y = 0

(4D^5-23D^3-33D^2-17D-3)y=0

(4 D^{5} - 23 D^{3} - 33 D^{2} - 17 D - 3) y = 0

(d^2x)/(dt^2)+5(dx)/(dt)+4x=0

\frac{d ^{2} x}{d t ^{2}} + 5 \frac{d x}{d t} + 4 x = 0

y^{^{''}} - 7 y^{^{'}} = 0

y^{''}-6y^'+13y=0,y(0)=e^{3x}cos(2x)

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = e^{3 x} cos (2 x)