y^{''}-5y^'+6y=2x+1

Lösung

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 x + 1

y = c_{1} e^{3 x} + c_{2} e^{2 x} + \frac{x}{3} + \frac{4}{9}

Schritte zur Lösung

y^{''} (x) - 5 y^{'} (x) + 6 y = 2 x + 1

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{2 x} + \frac{x}{3} + \frac{4}{9}

y = c_{1} e^{3 x} + c_{2} e^{2 x} + \frac{x}{3} + \frac{4}{9}

4 x^{^{''}} + x = t^{2} + 2 cos (t)

y^{^{''}} - 4 y + 4 = - 5 e^{3 x}

x^{^{''}} + 4 x = cos (4 t)

x^{^{''}} - 2 x^{^{'}} + 3 x + 2 = 0

y^{^{''}} - 10 y^{^{'}} + 16 = 0