y^{''}+2y=cos(t)

Lösung

y^{^{''}} + 2 y = cos (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + cos (t)

Schritte zur Lösung

y^{''} (t) + 2 y = cos (t)

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + cos (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + cos (t)

y^{^{''}} - y^{^{'}} = x^{2} + 2 x + 3

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} - 32 y = 6 + 3 x

y^{^{''}} + a y^{^{'}} - 2 a^{2} y = 1

y^{^{''}} + 2 y^{^{'}} + y = e^{- x}, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} + 6 y^{^{'}} + 9 y = 2 e^{(- 3 x)} \frac{1}{x ^{2} + 1}