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Beliebt Rechnen >

y^{''}+4y^'+40y=12.5sin(6t)

Lösung

y^{^{''}} + 4 y^{^{'}} + 40 y = 12.5 sin (6 t)

Lösung

y = e^{- 2 t} (c_{1} cos (6 t) + c_{2} sin (6 t)) + 0.08445 \dots sin (6 t) - 0.50675 \dots cos (6 t)

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + 40 y = 12.5 sin (6 t)

Solve linear ODE:

y = e^{- 2 t} (c_{1} cos (6 t) + c_{2} sin (6 t)) + 0.08445 \dots sin (6 t) - 0.50675 \dots cos (6 t)

y = e^{- 2 t} (c_{1} cos (6 t) + c_{2} sin (6 t)) + 0.08445 \dots sin (6 t) - 0.50675 \dots cos (6 t)

Graph

Beliebte Beispiele

y^{''}+3y^'-28y=-96t+56t^2

y^{^{''}} + 3 y^{^{'}} - 28 y = - 96 t + 56 t^{2}

θ^{''}(t)-θ(t)=t

θ^{^{''}} (t) - θ (t) = t

linear y^{'''}+y^'=sec(x)

l in e a r y^{^{'''}} + y^{^{'}} = sec (x)

y^{'''}-11y^{''}+35y^'-25=0

y^{^{'''}} - 11 y^{^{''}} + 35 y^{^{'}} - 25 = 0

(d^2y)/(dt^2)+2y=cos(7t)

\frac{d ^{2} y}{d t ^{2}} + 2 y = cos (7 t)