What is the solution for -5y^{''}-2y^'+24=0 ?

The solution for -5y^{''}-2y^'+24=0 is y=c_{1}e^{-(2t)/5}+c_{2}+12t

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-5y^{''}-2y^'+24=0

- 5 y^{^{''}} - 2 y^{^{'}} + 24 = 0

y = c_{1} e^{- \frac{2 t}{5}} + c_{2} + 12 t

Solution steps

- 5 y^{''} (t) - 2 y^{'} (t) + 24 = 0

Solve linear ODE:

y = c_{1} e^{- \frac{2 t}{5}} + c_{2} + 12 t

y = c_{1} e^{- \frac{2 t}{5}} + c_{2} + 12 t

What is the solution for -5y^{''}-2y^'+24=0 ?
The solution for -5y^{''}-2y^'+24=0 is y=c_{1}e^{-(2t)/5}+c_{2}+12t