What is the solution for y^{''}-6y^'+9y=15x+6 ?

The solution for y^{''}-6y^'+9y=15x+6 is y=c_{1}e^{3x}+c_{2}xe^{3x}+(5x)/3+16/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-6y^'+9y=15x+6

y^{^{''}} - 6 y^{^{'}} + 9 y = 15 x + 6

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + \frac{5 x}{3} + \frac{16}{9}

Solution steps

y^{''} (x) - 6 y^{'} (x) + 9 y = 15 x + 6

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + \frac{5 x}{3} + \frac{16}{9}

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + \frac{5 x}{3} + \frac{16}{9}

y^{^{''}} + 4 y = x^{2} + 2 e^{x}

y^{^{''}} + 81 y = 2 sin (x)

y^{^{''}} + 8 y^{^{'}} + \frac{1}{2} y = 10 sin (4 x)

y^{^{'''}} - 4 y^{^{''}} + 5 y^{^{'}} - 2 y = 6 \cdot e^{x} + 10 cos (x)

y^{^{''}} + 3 y^{^{'}} + 2 y = H (2)

What is the solution for y^{''}-6y^'+9y=15x+6 ?
The solution for y^{''}-6y^'+9y=15x+6 is y=c_{1}e^{3x}+c_{2}xe^{3x}+(5x)/3+16/9