y^{''}+y^'=x,y(0)=8,y^'(0)=0

Lösung

y^{^{''}} + y^{^{'}} = x, y (0) = 8, y^{^{'}} (0) = 0

y = \frac{x ^{2}}{2} - x - e^{- x} + 9

Schritte zur Lösung

y^{''} (x) + y^{'} (x) = x

Solve linear ODE:

y = \frac{x ^{2}}{2} - x - e^{- x} + 9

y = \frac{x ^{2}}{2} - x - e^{- x} + 9

y^{^{''}} + 4 y = 3 cos (2 t), y (0) = 1, y^{^{'}} (0) = 0

0.125 y^{^{''}} + 106 y + 1000 = 0

y^{^{''}} + y^{^{'}} = 1, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} arctan (x)

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = x^{2} + x