y^{''}+y^'-6=2x

Lösung

y^{^{''}} + y^{^{'}} - 6 = 2 x

y = c_{1} + c_{2} e^{- x} + x^{2} + 4 x

Schritte zur Lösung

y^{''} (x) + y^{'} (x) - 6 = 2 x

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + x^{2} + 4 x

y = c_{1} + c_{2} e^{- x} + x^{2} + 4 x

y^{^{''}} - 2 y^{^{'}} - 3 y = 2 x e^{3 x}

y^{^{''}} - 2 y^{^{'}} = 8 x

0.5 y^{^{''}} + 6 y^{^{'}} + 50 y = 240 cos (10 t)

y^{^{''}} + y = 4 \cdot cos (x)

y^{^{''''}} - y = 8 t + cos (t)