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Beliebt Rechnen >

y^{''}+2y^'=8x^3

Lösung

y^{^{''}} + 2 y^{^{'}} = 8 x^{3}

Lösung

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) = 8 x^{3}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

y = c_{1} + c_{2} e^{- 2 x} + x^{4} - 2 x^{3} + 3 x^{2} - 3 x

Graph

Beliebte Beispiele

y^{''}-4y^'+4y=e^{2x}*sin(x)

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} \cdot sin (x)

linear (d^2x)/(dt^2)+(dx)/(dt)=6t

l in e a r \frac{d ^{2} x}{d t ^{2}} + \frac{d x}{d t} = 6 t

y^{''}+9y=9cos^3(3x)

y^{^{''}} + 9 y = 9 cos^{3} (3 x)

y^{''}+2y^'+1=te^tsin(t)

y^{^{''}} + 2 y^{^{'}} + 1 = t e^{t} sin (t)

y^{''''}+2y^{''}+y=3t+10

y^{^{''''}} + 2 y^{^{''}} + y = 3 t + 10