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Beliebt Rechnen >

y^{''}+2y^'+y=cos(3x)

Lösung

y^{^{''}} + 2 y^{^{'}} + y = cos (3 x)

Lösung

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{3}{50} sin (3 x) - \frac{2}{25} cos (3 x)

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) + y = cos (3 x)

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{3}{50} sin (3 x) - \frac{2}{25} cos (3 x)

y = c_{1} e^{- x} + c_{2} x e^{- x} + \frac{3}{50} sin (3 x) - \frac{2}{25} cos (3 x)

Graph

Beliebte Beispiele

y^{''}-4y=(x+5e^{2x})/(e^{2x)}

y^{^{''}} - 4 y = \frac{x + 5 e ^{2 x}}{e ^{2 x}}

y^{''}-2y^'+y=x^3+7x

y^{^{''}} - 2 y^{^{'}} + y = x^{3} + 7 x

y^{''}+6y^'+34y=68

y^{^{''}} + 6 y^{^{'}} + 34 y = 68

x^{''}+16x=cos(2t)

x^{^{''}} + 16 x = cos (2 t)

y^{''}+2y^'=2e^{-2t}

y^{^{''}} + 2 y^{^{'}} = 2 e^{- 2 t}