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Beliebt Rechnen >

y^{''}-4y^'=16t+36,y(-2)=2,y^'(-2)=-1

Lösung

y^{^{''}} - 4 y^{^{'}} = 16 t + 36, y (- 2) = 2, y^{^{'}} (- 2) = - 1

Lösung

y = \frac{e ^{8}}{4} e^{4 t} - \frac{41}{4} - 2 t^{2} - 10 t

Schritte zur Lösung

y^{''} (t) - 4 y^{'} (t) = 16 t + 36

Solve linear ODE:

y = \frac{e ^{8}}{4} e^{4 t} - \frac{41}{4} - 2 t^{2} - 10 t

y = \frac{e ^{8}}{4} e^{4 t} - \frac{41}{4} - 2 t^{2} - 10 t

Graph

Beliebte Beispiele

(d^2y)/(dx^2)+a(dy)/(dx)=b

\frac{d ^{2} y}{d x ^{2}} + a \frac{d y}{d x} = b

y^{''}+36y=12tan(6t)

y^{^{''}} + 36 y = 12 tan (6 t)

(-8x^{''}-16x^'+24)=8e^{2t}

(- 8 x^{^{''}} - 16 x^{^{'}} + 24) = 8 e^{2 t}

y^{''}-y^'+2y=4e^x

y^{^{''}} - y^{^{'}} + 2 y = 4 e^{x}

(4d^4+20d^3+35d^2+25d+6)y=o

(4 d^{4} + 20 d^{3} + 35 d^{2} + 25 d + 6) y = o