What is the integral of 1/(6x) ?

The integral of 1/(6x) is 1/6 ln|x|+C

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integral of 1/(6x)

\int \frac{1}{6 x} d x

\frac{1}{6} ln ∣ x ∣ + C

Solution steps

\int \frac{1}{6 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{6} ln ∣ x ∣

Add a constant to the solution

= \frac{1}{6} ln ∣ x ∣ + C

(t - sin (t))^{^{'}}

n = 1 \sum \infty \frac{4}{n ln ( 8 n )}

d er i v a t i v e f (x) = 17 x

d er i v a t i v e \frac{8 t}{8 + t}

\int \frac{3 x ^{2}}{2} d x