We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for 2y^{''}+3y^'+4y=0 ?
- The solution for 2y^{''}+3y^'+4y=0 is y=e^{-(3t)/4}(c_{1}cos((sqrt(23)t)/4)+c_{2}sin((sqrt(23)t)/4))