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Beliebt Rechnen >

y^{''}+2y^'+2y=(e^{-x})/(cos(x))

Lösung

y^{^{''}} + 2 y^{^{'}} + 2 y = \frac{e ^{- x}}{cos ( x )}

Lösung

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- x} cos (x) + x e^{- x} sin (x)

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) + 2 y = \frac{e ^{- x}}{cos ( x )}

Solve linear ODE:

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- x} cos (x) + x e^{- x} sin (x)

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- x} cos (x) + x e^{- x} sin (x)

Graph

Beliebte Beispiele

y^{^{''}} - y = ln (t)

y^{''}-12y^'+36y=12x+5

y^{^{''}} - 12 y^{^{'}} + 36 y = 12 x + 5

y^{''}+4y=t^2+2e^t,y(0)=0,y^'(0)=3

y^{^{''}} + 4 y = t^{2} + 2 e^{t}, y (0) = 0, y^{^{'}} (0) = 3

y^{''}+2y^'+2y=2cos(2t)

y^{^{''}} + 2 y^{^{'}} + 2 y = 2 cos (2 t)

y^{''}+2y^'+5y=2sin(t)

y^{^{''}} + 2 y^{^{'}} + 5 y = 2 sin (t)